Resistor
Moderator: Dave Mudgett
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Resistor
How would the tone of the guitar be affected if a resistor were placed on the jack? Or
in the case of an Emmons, if the size of the
resistor on the pot were changed? Thanks
in the case of an Emmons, if the size of the
resistor on the pot were changed? Thanks
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Generally, a resistor will not affect the tone...only the how fast (or how slow) the volume comes on. But, there's a lot of variables here, so each case is unique. More importantly, remember that any resistance added in the signal path will lower the power, or available volume. I have never been able to get the sound I want from a low powered amp, or even a big amp, with the volume controls turned to anything but full-on, or nearly so.
But that's just me.
But that's just me.
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To get the best possible full range freq responce from the instrument,if possible one should not use any kind of resistance in-line or across the P/U. Any Tech will tell you this. A resistance across the jack will result in:
1) A set amount of signal to the amp.
2) A roll-off of freq responce at certain freqs,depending upon the value of the resistor.
3) Is self-defeating the very need for EQ.
If you restrict the freqs that make the instrument sound good, EQ equipment is a waste of money.
Being that I'm haveing a somewhat senior moment right now, I think that a resistance value will roll-off the bass responce and a cap will roll-off the high freqs.
Needless to say, anything you place across or in-line with the signal line will affect the resultant sound.
1) A set amount of signal to the amp.
2) A roll-off of freq responce at certain freqs,depending upon the value of the resistor.
3) Is self-defeating the very need for EQ.
If you restrict the freqs that make the instrument sound good, EQ equipment is a waste of money.
Being that I'm haveing a somewhat senior moment right now, I think that a resistance value will roll-off the bass responce and a cap will roll-off the high freqs.
Needless to say, anything you place across or in-line with the signal line will affect the resultant sound.
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First of all, asking anyone about how something's going to sound if you do something is going to get you a bunch of different answers, all of them trying to describe a sound and having a sound described to you doesn't really tell you anything. The only way to test effects of component changes in a circuit is to do them and listen. I DON'T mean start soldering junk into your amp or steel. Here's what to do: Set up your amp and steel somewhere and turn on the amp. Grab a guitar cord with an unscrewable metal end. Unscrew the cords' end cover so the cord's connections are exposed at the end that plugs into the steel. If you want to test a cap or resistor in parallel (across both the center lead and the ground shield braid) you can just hold it on there with one hand while picking strings on the steel with the other. Or, you can use alligator clip-leads so you can sit at the steel and actually play with the part clipped into the circuit. Then unclip the part and play again and you can hear the part in and out of the circuit. You'll get some hum doing this because of the unshielded clip leads. If you want to test a part in series, use a cord you don't mind messing with, unsolder the center connection and do the rest the same way as above except connection the part one end to the unsoldered cord wire and the other end to the jack where you unsoldered it from. That may seem like a lot to go through just to find out what something sounds like, and I'm sure some will say "forget it". It's the only real way to find out and therefore I think it's worth it I you really want to know. I pick my tone capacitors for my guitars this way. By the way, not entirely on the same subject but speaking of resistance, if your volume pot doesn't drop the resistance all the way down to zero ohms when it's all the way up, you lose some high frequencies. I've found many pots have levels of resistance, some quite high, when turned all the way up and this should not be. You have to unsolder one of the connections if you want to check it. <FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Jim Phelps on 24 January 2002 at 08:09 AM.]</p></FONT>
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Short answer: If all you want to do is roll off some highs, you can use a capacitor of .001 to maybe a .002, and you want it in parallel, that's one end connected to center and one to ground. You would have to pick the value of the cap according to just how much of the highs you want rolled off. Keep in mind, other times you might not want that. You could get an e.q. box, that way you don't do anything permanent. Or solder the cap into one cord, use it when you want to roll off highs. If you're used to soldering and making mods on guitars you could put a miniswitch somewhere to select between 2 caps, with a center-off position. I did this on one of my guitars that had no tone control and was too bright, works great.
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You're right Steve, but in the case of a pickup it's not the resistance itself that makes that fatter tone as much as it's because more wire makes more output, more capacitance (also causing less highs and more mid) and inductance. The higher resistance is because of the high number of turns of wire. And anyway that's what we've been saying here, more resistance, less highs although the question was about inserting a resister into the circuit, not a pickup with more resistance. <FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Jim Phelps on 24 January 2002 at 01:49 PM.]</p></FONT>
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Or just turn the treble all the way up and make it sound like (whatever it is Jack plays).
I've got a Sho-Bud with a 710 pickup and a stock MSA and both of them practically tear your head off with treble if I play them in my old '82 Music Man amp with EV speaker even with the bright switch off and the treble on 0! Bill didn't say what kind of amp he's using. It could be like my MM. I doubt he doesn't know what his amps tone knobs are for.<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Jim Phelps on 24 January 2002 at 08:47 PM.]</p></FONT>

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