A method for decreasing detune due to cabinet flex
Posted: 10 Sep 2010 6:46 am
At the risk of beating a topic to death.....
PSG Cabinet detune – the effect observed whereby raising the pitch of one or more strings drops the pitch slightly on those strings not raised.
I noticed a while ago while working with a steel guitar maker that cabinet detune gets worse in proportion to the number of strings a guitar has.
I'm talking single necks on like body here only for the time being. That is, a 10 string guitar has a small amount of detune, a 12 string guitar on the same cabinet has more detune, and a 14 string guitar on same cabinet has even more. It just so happened there were three like bodied guitars in one place at the same time, a single 10, single 12 (mine) and a new single 14. At the time we had access to a fine movement measuring device and determined the following. Detune is mainly a result of the top body wood flexing. Yes, the gauge of the string and whether it is wound or not makes it more or less sensitive. Yes, the amount of pedal pressure one mashes the pedals with affects the detune, (the best argument for raise helper springs) However, I believe the primary cause is: the sum of the collective tension that the group of strings apply to the top side in relation to the stiffness of the top wood is responsible for the degree of detune.
The maker had also just built a couple of guitars with high quality jig board plywood rather than maple and these guitars had exhibited more detune than the maple ones. Tests with the position gauge and weights confirmed that the ply did indeed flex more than the maple when a weight was place in the middle with its sides supported.
This is also supported buy another casual observation I made. I had owned an earlier vintage PSG that was a thick bodied guitar. The wooden neck is one inch thick and the top wood is also one inch thick on this design. This guitar had very little detune. Unfortunately, I never liked the tone of this particular guitar.
Since the all the string tension is on one side of the top wood, and the strings sit an average of 1.25" above the top, the top flexes or bows. My guitar as well as many newer brands uses a 0.625" thick top. I theorize that a thinner top makes for a louder better sounding guitar (Emmons for example). I really like the tone of my guitar but it does detune more than I would prefer.
Here's my hypothesis: Once the top of a PSG is bowed it gets progressively easier to bow it further by increasing the tension of a string. This accounts for the behavior noted above. The bow in relationship to the compression force is not a linear function but rather is logarithmic until finally the piece breaks.
I mentioned this to a mechanical engineer and he said my theory is supported by Euler's buckling theorem. Euler was a mathematician in the 1700s who described stress affects with formulas.
So how do we reduce top wood flexing?
One possibility is to lower the strings. I saw a home made PSG with no neck and the strings were only 3/8” off the body. This guitar had very little detune but it was ugly as sin and didn’t sound very good to boot.
The method I would like to try is to incorporate a truss rod so to speak. That is, attach a metal rod that runs from end to end on the underside of the PSG with a turnbuckle in the middle. Perhaps it would be integral with the key head and changer some how such that one could pull the buckle out of the top of a fully strung guitar by turning the turnbuckle. According Euler’s buckling theorm, once the top is straight it would take a very high force to start it bending again. This force would be more than a single or dual string pitch raise could apply.
There may be reasons this is impractical. We are talking very fine movement here.
Temperature and humidity may require we constantly adjust the tension.
How do you know how much tension to apply?
Will it affect the tone?
More wieght and complexity - maybe not be worth it.
Any thoughts?
PSG Cabinet detune – the effect observed whereby raising the pitch of one or more strings drops the pitch slightly on those strings not raised.
I noticed a while ago while working with a steel guitar maker that cabinet detune gets worse in proportion to the number of strings a guitar has.
I'm talking single necks on like body here only for the time being. That is, a 10 string guitar has a small amount of detune, a 12 string guitar on the same cabinet has more detune, and a 14 string guitar on same cabinet has even more. It just so happened there were three like bodied guitars in one place at the same time, a single 10, single 12 (mine) and a new single 14. At the time we had access to a fine movement measuring device and determined the following. Detune is mainly a result of the top body wood flexing. Yes, the gauge of the string and whether it is wound or not makes it more or less sensitive. Yes, the amount of pedal pressure one mashes the pedals with affects the detune, (the best argument for raise helper springs) However, I believe the primary cause is: the sum of the collective tension that the group of strings apply to the top side in relation to the stiffness of the top wood is responsible for the degree of detune.
The maker had also just built a couple of guitars with high quality jig board plywood rather than maple and these guitars had exhibited more detune than the maple ones. Tests with the position gauge and weights confirmed that the ply did indeed flex more than the maple when a weight was place in the middle with its sides supported.
This is also supported buy another casual observation I made. I had owned an earlier vintage PSG that was a thick bodied guitar. The wooden neck is one inch thick and the top wood is also one inch thick on this design. This guitar had very little detune. Unfortunately, I never liked the tone of this particular guitar.
Since the all the string tension is on one side of the top wood, and the strings sit an average of 1.25" above the top, the top flexes or bows. My guitar as well as many newer brands uses a 0.625" thick top. I theorize that a thinner top makes for a louder better sounding guitar (Emmons for example). I really like the tone of my guitar but it does detune more than I would prefer.
Here's my hypothesis: Once the top of a PSG is bowed it gets progressively easier to bow it further by increasing the tension of a string. This accounts for the behavior noted above. The bow in relationship to the compression force is not a linear function but rather is logarithmic until finally the piece breaks.
I mentioned this to a mechanical engineer and he said my theory is supported by Euler's buckling theorem. Euler was a mathematician in the 1700s who described stress affects with formulas.
So how do we reduce top wood flexing?
One possibility is to lower the strings. I saw a home made PSG with no neck and the strings were only 3/8” off the body. This guitar had very little detune but it was ugly as sin and didn’t sound very good to boot.
The method I would like to try is to incorporate a truss rod so to speak. That is, attach a metal rod that runs from end to end on the underside of the PSG with a turnbuckle in the middle. Perhaps it would be integral with the key head and changer some how such that one could pull the buckle out of the top of a fully strung guitar by turning the turnbuckle. According Euler’s buckling theorm, once the top is straight it would take a very high force to start it bending again. This force would be more than a single or dual string pitch raise could apply.
There may be reasons this is impractical. We are talking very fine movement here.
Temperature and humidity may require we constantly adjust the tension.
How do you know how much tension to apply?
Will it affect the tone?
More wieght and complexity - maybe not be worth it.
Any thoughts?